Discussion
An instrument has \( 0.1 \) per cent stray light. Its maximum measurable absorbance is about
Answer: D
Even with the sample absorbing everything, the stray light still reaches the detector:
\[ A_{max} = -\log_{10}(0.001) = 3 \]
giving about 3, and readings approaching it are increasingly compressed and non-linear. Reducing stray light by a factor of ten buys one more unit of absorbance, which is why high-absorbance work needs a double monochromator rather than a better detector.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development