Discussion
A sample reads \( 1.8 \) absorbance. Diluting it fourfold gives about
Answer: D
Concentration falls fourfold and absorbance follows in proportion:
\[ A = \frac{1.8}{4} = 0.45 \]
giving about 0.45, squarely in the band where photometric error is least. A twofold dilution would have left it at 0.9, still usable but further up the curve. Choosing a dilution factor that lands the reading in the low-error band, rather than merely reducing it, is what makes the second measurement worth making.
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