Discussion
A double-beam instrument reads \( 0.65 \) with the sample in place. If the blank alone reads \( 0.05 \) against air, the sample's corrected absorbance is
Answer: C
Subtracting the blank's own contribution:
\[ A = 0.65 - 0.05 = 0.60 \]
giving 0.60. In normal use the blank sits in the reference path and the subtraction happens automatically, which is exactly why the instrument reads 0.60 directly when set up properly. Understanding what the automatic correction is doing matters when a reading has to be checked or a blank is suspect.
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