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A proton signal is split into 5 lines. The number of equivalent neighbouring protons is

  • A.6
  • B.4
  • C.5
  • D.3

Answer: B

Correct answer: 4

The multiplicity is \( n + 1 \), so five lines mean

\[ n = 5 - 1 = 4 \]

equivalent neighbouring protons, giving a quintet with intensities 1:4:6:4:1. The middle methylene of a propyl chain flanked by a methyl and another methylene shows exactly this pattern.

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