Discussion
The number of signals exhibited by fluoroacetone in 1H-NMR spectrum is :
Answer: A
Fluoroacetone (FCH2COCH3) shows two doublets.
It has two kinds of protons. The CH2F protons are split by the fluorine (19F, I = 1/2) on the same carbon, a large geminal coupling of about 47 Hz, giving a doublet. The CH3 protons are four bonds from the fluorine, through the carbonyl group, and show a small long-range H-F coupling of a few hertz, so they too appear as a doublet.
The two sets of protons are separated by the carbonyl carbon and do not couple with each other, so no triplet arises. Treating the methyl group as a singlet ignores the four-bond H-F coupling that the key counts.
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