Machine-translated by Google. Questions are authored in English.
Top

Discussion

The ratio of relative intensities of the two molecular ion peaks of methyl bromide (CH3Br) in the mass spectrum is

  • A.M\(^{+}\) : (M+2)\(^{+}\) = 1:3
  • B.M\(^{+}\) : (M+2)\(^{+}\) = 3:1
  • C.M\(^{+}\) : (M+2)\(^{+}\) = 1:1
  • D.M\(^{+}\) : (M+2)\(^{+}\) = 1:2

Answer: C

The M+ and (M+2)+ peaks are in the ratio 1:1.

Bromine has two stable isotopes, 79Br (about 50.7%) and 81Br (about 49.3%), two mass units apart and almost equally abundant. CH379Br gives the molecular ion at m/z 94 and CH381Br the ion at m/z 96, so the two peaks are of nearly equal height.

3:1 is the pattern of chlorine (35Cl : 37Cl), which is the usual trap here. 1:3 reverses it, and 1:2 matches no single halogen.

No comment is present. Be the first to comment.
Loading…

Post your comment

Please log in or register to post a comment.