Discussion
A sprinkler irrigation system has been designed for a crop with the water application rate of 1.17 cm h-1 and sprinkler discharge of 1.3 L s-1. The coefficient of discharge and uniformity coefficient are 0.9 and 0.8, respectively. If the sprinkler spacing along the lateral is 20 m, the lateral spacing in m is
Answer: D
The lateral spacing is 20.0 m.
A sprinkler's application rate is its discharge spread over the area it serves, sprinkler spacing times lateral spacing:
\[ \begin{aligned} q &= 1.3\ \text{L/s} = 4.68\ \text{m}^{3}/\text{h} \\ S_{l} S_{m} &= \frac{q}{I} = \frac{4.68}{0.0117} = 400\ \text{m}^{2} \\ S_{m} &= \frac{400}{20} = 20\ \text{m} \end{aligned} \]
The discharge given is already the actual sprinkler discharge, so the key does not apply the coefficient of discharge or the uniformity coefficient again. The distractors come from doing so: multiplying the area by 0.9 gives 18.0 m, by 0.8 gives 16.0 m, and by both (0.72) gives 14.4 m.
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development