Discussion
\(\sqrt[3]{4\dfrac{12}{125}}\text{ = ?}\)
Answer: C
\(\sqrt[3]{4\dfrac{12}{125}}\\=\sqrt[3]{\dfrac{512}{125}}\\ = \sqrt[3]{\dfrac{2\times 2 \times 2 \times 2\times 2 \times 2 \times 2\times 2 \times 2}{5 \times 5 \times 5}}\\ =\dfrac{2\times 2 \times 2 }{5}\\ = \dfrac{8}{5}\\ = 1\dfrac{3}{5}\)
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