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If x is the smallest number which is to be subtracted from 2605 to make it a perfect square, then the value of (4x + 7) is :

  • A.31
  • B.11
  • C.23
  • D.27

Answer: C

The value of \((4x + 7)\) is 23.

The largest perfect square not exceeding 2605 is \(51^2 = 2601\), since \(52^2 = 2704\). So the smallest number to subtract is

\[ \begin{aligned} x &= 2605 - 2601 = 4 \\ 4x + 7 &= 16 + 7 = 23 \end{aligned} \]

31 would need x = 6, 27 would need x = 5, and 11 would need x = 1, none of which leaves a perfect square.

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