Discussion
Match List I with List II and select the correct answer using codes given below :
| List I (Characteristic Equation of the System) | List II (Stability of the System) |
|---|---|
| (a) \(s^{5} + s^{4} + 2s^{3} + 2s^{2} + 3s + 15 = 0\) | (i) marginally stable |
| (b) \(s^{6} + 2s^{5} + 8s^{4} + 12s^{3} + 20s^{2} + 16s + 16 = 0\) | (ii) unstable |
| (c) G(s) H(s) = 10/s (s + 2) (s + 5) | (iii) stable |
| (d) \(G(s) = \dfrac{s + 5}{s^{2} + 4s + 9}\) | (iv) phase angle of the system varies between 0° and -90°. |
Answer: A
The correct matching is a-ii, b-i, c-iii, d-iv.
- (a) In the Routh array of s5 + s4 + 2s3 + 2s2 + 3s + 15, the s3 row starts with zero (2 - 2 = 0); replacing it by a small ε gives two sign changes in the first column, so two roots lie in the right half plane: unstable (ii).
- (b) The Routh array of the sixth-order polynomial produces a row of zeros whose auxiliary polynomial has roots on the imaginary axis, with no sign change in the first column: marginally stable (i).
- (c) With GH = 10/s(s + 2)(s + 5), the characteristic equation is s3 + 7s2 + 10s + 10 = 0; since \(7 imes 10 = 70 \gt 10\), all roots are in the left half plane: stable (iii).
- (d) G(s) = (s + 5)/(s2 + 4s + 9) has phase 0° at zero frequency and approaches -90° at high frequency, since it has one more pole than zero (iv).
The other codes call the polynomial with a right-half-plane pair marginally stable or the third-order loop unstable, which the Routh test rules out.
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