Discussion
A rudder produces \( 0.0018 \) of yawing moment coefficient per degree. To generate \( 0.036 \) it must deflect
Answer: C
Correct answer: 20 degrees
Rudder power is the moment per degree, so the deflection needed follows by division:
\[ \delta_r = \frac{C_n}{C_{n\delta r}} = \frac{0.036}{0.0018} = 20^\circ \]
The result is worth checking against the physical limit. Rudder travel is typically restricted to about 25 to 30 degrees, so 20 degrees is a large but usable deflection - there is little margin left. That is the kind of margin a designer examines when sizing the rudder for the engine-out case, since a demand beyond the stop means the condition cannot be held at all.
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