Discussion
A fin of \( 12 \ \mathrm{m^2} \) at an arm of \( 12 \ \mathrm{m} \) must generate \( 720 \ \mathrm{kN\,m} \). The side force required is
Answer: A
Correct answer: 60 kN
Force follows from moment divided by arm:
\[ F = \frac{N}{l} = \frac{720}{12} = 60\ \mathrm{kN} \]
The fin area of 12 m\(^2\) is not needed for this step - it would be used next, to find the side force coefficient required and hence the sideslip or rudder angle to generate it. Noticing which data the question actually needs is half the work. The arm is what converts between force and moment, which is why lengthening the fuselage is as effective a way of improving directional stability as enlarging the fin.
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