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An aeroplane's minimum control speed in the air is \( 92 \ \mathrm{kt} \) and its stalling speed \( 88 \ \mathrm{kt} \). The margin between them is

  • A.180 knots
  • B.0.96 knots
  • C.4 knots, with control speed the higher
  • D.4 knots, with stall speed the higher

Answer: C

Correct answer: 4 knots, with control speed the higher

The margin is the difference, and its sign is what the question tests:

\[ 92 - 88 = 4\ \mathrm{kt} \]

with \( V_{MCA} \) above \( V_S \). That ordering is required by certification, since an aeroplane that lost directional control before it stalled would be uncontrollable while still flying. It also explains why the take-off safety speed \( V_2 \) is set above both, and why on this aeroplane the controlling limit at low speed is the rudder rather than the wing - a small margin, so the engine-out case governs.

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