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An aeroplane weighs \( 60 \ \mathrm{kN} \) and its tail carries a download of \( 3 \ \mathrm{kN} \) in trim. The wing lift required is

  • A.63 kN
  • B.57 kN
  • C.60 kN
  • D.180 kN

Answer: A

Correct answer: 63 kN

Vertical equilibrium takes the tail download as a load the wing must also carry:

\[ L_w = W + L_t = 60 + 3 = 63 \text{ kN} \]

The wing therefore works five per cent harder than the weight alone would require, and the induced drag rises with the square of that. Subtracting the download, which gives 57 kN, would be right only for a canard, whose foreplane lifts upward.

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