Discussion
A silo of \( 6.0 \) m diameter is filled to \( 14 \) m with grain of bulk density \( 770 \) kg/m\(^3\). The mass stored is
Answer: A
Correct answer: 305 tonnes
Find the volume of the filled cylinder, then multiply by the bulk density:
\[ V = \pi r^2 h = \pi (3.0)^2 (14) = 395.8\ \mathrm{m}^3 \]
\[ m = 395.8 \times 770 = 304\,800\ \mathrm{kg} = 305\ \mathrm{tonnes} \]
The distractor \( 396 \) is the volume in cubic metres mistaken for tonnes, and \( 1220 \) would follow from using the diameter as the radius. Note that bulk density, not grain density, is the right figure - it already accounts for the void space between kernels.
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