Discussion
Aeration at \( 0.12 \) m\(^3\) per minute per tonne is applied to \( 300 \) tonnes. The fan must deliver
Answer: B
Correct answer: 36 m\(^3\) per minute
The fan duty is the specific aeration rate times the tonnage:
\[ Q = 0.12\ \mathrm{m^3/min/t} \times 300\ \mathrm{t} = 36\ \mathrm{m^3/min} \]
This is a modest flow for a large mass of grain, which is the character of aeration - enough to move a cooling front through the bulk over a day or more, not enough to dry it. The fan must nonetheless develop appreciable static pressure, because the resistance of a deep packed bed of grain is high.
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