Discussion
A cold store holds \( 40 \) tonnes of produce cooled from \( 25 \) to \( 4 \) degrees Celsius, with a specific heat of \( 3.8 \) kJ/kg K. The field heat to be removed is
Answer: D
Correct answer: 3192 MJ
The sensible heat removed is mass times specific heat times temperature drop:
\[ Q = mc\Delta T = 40\,000 \times 3.8 \times (25-4) = 40\,000 \times 3.8 \times 21 \]
\[ Q = 3\,192\,000\ \mathrm{kJ} = 3192\ \mathrm{MJ} \]
This is the product load alone. Respiration, transmission and infiltration must be added before the plant is sized, and the pull-down time matters as much as the total: 3192 MJ removed over 24 hours is about 37 kW, but over 8 hours it is 111 kW.
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