Discussion
A fastener of \( 5 \) mm diameter bears on \( 2 \) mm sheet carrying \( 4 \) kN. The bearing stress is
Answer: B
Correct answer: 400 MPa
Bearing stress uses the projected area of the hole, that is diameter times thickness:
\[ \sigma_{br} = \frac{P}{dt} = \frac{4000}{0.005 \times 0.002} = \frac{4000}{10^{-5}} = 4 \times 10^8 \ \mathrm{Pa} = 400 \ \mathrm{MPa} \]The projected rectangle, not the hole’s circular area, is the convention, and it is what bearing allowables are quoted against.
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