Discussion
What is the output of following program?
# include <stdio.h>
int main()
{
char str1[] = "GeeksQuiz";
char str2[] = {'G', 'e', 'e', 'k', 's', 'Q', 'u', 'i', 'z'};
int n1 = sizeof(str1)/sizeof(str1[0]);
int n2 = sizeof(str2)/sizeof(str2[0]);
printf("n1 = %d, n2 = %d", n1, n2);
return 0;
}
Answer: A
Correct answer: n1 = 10, n2 = 9
str1 is initialised from a string literal, so the compiler adds a terminating null: 9 letters plus '\0' is 10 bytes. str2 is initialised from an explicit list of nine characters, with no null added, so it is 9 bytes - and, lacking a terminator, it is an array of characters rather than a usable C string.
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