Discussion
What does the function void *memmove(void *s1, const void *s2, size_t n); return?
Answer: A
Correct answer: returns the value of s1
memmove returns its destination pointer, s1 - as memcpy, strcpy and strcat all do. Returning the destination lets a call be used directly as an argument to another function. Its distinctive property is that it works correctly even when the two regions overlap, which memcpy does not guarantee.
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