Discussion
What does void *memcpy(void *dest, const void *src, size_t n) do?
Answer: A
Correct answer: copies n characters from src to dest
memcpy copies n bytes from src to dest - destination first, as throughout the library. The source is const because it is only read, and the return value is the destination pointer. The two regions must not overlap; memmove is the version that handles overlap correctly.
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