Discussion
What will be the output of the following C code?
#include <stdio.h>
int main()
{
char str[11] = "hello";
char *str1 = "world";
strcat(str, str1);
printf("%s %d", str, str[10]);
}
Answer: A
Correct answer: helloworld 0
strcat appends world to hello, giving ten characters, and writes the terminating null at index 10 - the last element of the eleven-byte array. So str[10] is '\0', and %d prints its value, 0. The array is exactly big enough; a char str[10] would have overflowed.
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