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What will be the output of the following C code?

#include <stdio.h>
    int main()
    {
        char str[10] = "hello";
        char *p = strrchr(str, 'l');
        printf("%c\n", *(++p));
    }

 

  • A.l
  • B.o
  • C.e
  • D.Compilation error

Answer: B

Correct answer: o

strrchr finds the last 'l', which in hello is at index 3. The pre-increment moves the pointer on one, to index 4, and that character is o.

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