Discussion
What will be the output of the program ?
#include <stdio.h>
#include <string.h>
int main()
{
static char s[] = "Hello!";
printf("%d\n", *(s+strlen(s)));
return 0;
}
Answer: D
Correct answer: 0
strlen(s) is 6, so s + 6 points at the byte just past Hello! - which is the terminating null. Dereferencing gives the character '\0', and %d prints its numeric value, 0.
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