Discussion
What will be the output of the program ?
#include <stdio.h>
int main()
{
char str[] = "Nagpur";
str[0]='K';
printf("%s, ", str);
str = "Kanpur";
printf("%s", str+1);
return 0;
}
Answer: D
Correct answer: Error
The first part is fine: str is a modifiable array, so str[0] = 'K' works. The failure is str = "Kanpur"; - an array name is not a modifiable lvalue, so it cannot be reassigned. Copying into it would need strcpy(str, "Kanpur"), and even then only if there were room.
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