Discussion
A panel \( 150 \) mm long and \( 2 \) mm thick carries equal stress at both ends. The boom area it contributes at each end is
Answer: B
The formula \( B = (t b/6)(2 + \sigma_2/\sigma_1) \) with a stress ratio of one gives \( (2 \times 150/6) \times 3 = 50 \times 3 = 150 \) mm\( ^2 \). That is half the panel area of 300 mm\( ^2 \), as it must be when the stress is uniform.
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