Discussion
Two stiffener elements have crippling stresses of \( 240 \) and \( 300 \) MPa with areas of \( 100 \) and \( 200 \) mm\( ^2 \). The section crippling stress is nearest to
Answer: D
Correct answer: 280 MPa
The section crippling stress is the area-weighted average of its elements:
\[ \sigma_{cc} = \frac{240(100) + 300(200)}{100 + 200} = \frac{84\,000}{300} = 280 \ \mathrm{MPa} \]The weighting matters - the simple average of 270 would understate the section, because the stronger element is twice the size. Each element buckles at its own stress and sheds load; the section stress is what the whole develops when they are combined.
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