Discussion
The number of sigma (σ) and pi (π ) bonds present in 3-Methylbut-1-ene are respectively
Answer: E
There are 14 and 1 sigma and pi bonds.
3-Methylbut-1-ene is \(CH_{2}=CH-CH(CH_{3})-CH_{3}\), formula \(C_{5}H_{10}\).
\[ \begin{aligned} \sigma(\text{C-H}) &= 10 \\ \sigma(\text{C-C}) &= 4 \\ \text{total } \sigma &= 14,\quad \pi = 1 \end{aligned} \]
The single C=C double bond is one sigma plus one pi bond (its sigma is counted among the 4 C-C bonds). Options with 2 pi bonds would need a diene or alkyne, and 1 and 14 swaps the numbers.
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