Discussion
On complete combustion of 0.96 g of an organic compound gives 0.88 g of carbon dioxide and 0.1 g of water. What is the percentage composition of carbon in the compound?
Answer: E
The percentage of carbon is 25%.
All the carbon ends up in \(CO_{2}\), which is \(\frac{12}{44}\) carbon by mass:
\[ \begin{aligned} m_{C} &= \frac{12}{44} \times 0.88 = 0.24\ \text{g} \\ \%C &= \frac{0.24}{0.96} \times 100 = 25\% \end{aligned} \]
The water figure is needed only for hydrogen. Taking the \(CO_{2}\) mass itself as a share of 0.96 g, or using 0.24 g out of a wrong total, gives the other options.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development