Discussion
What is the correct syntax to declare a function foo() which receives an array of structure in function?
Answer: A
Correct answer: void foo(struct *var);
An array argument decays to a pointer to its first element, so a function receiving an array of structures takes a pointer to structure. (In real code the tag must be named - void foo(struct tagname *var); - since struct alone is not a type.) Passing an array never copies it, so the length must be passed separately.
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