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What is the output of this program?

#include <stdio.h>
int main()
{
    enum days {MON=-1, TUE, WED=4, THU, FRI, SAT};
    printf("%d, %d, %d, %d, %d, %d", MON, TUE, WED, THU, FRI, SAT);
    return 0;
}

 

  • A.-1 0 4 5 6 7
  • B.-1 0 1 2 3 4
  • C.0 1 2 3 4 5
  • D.Error

Answer: A

Correct answer: -1 0 4 5 6 7

Enumerators continue from the last value given. MON is set to -1, so TUE is 0; WED is set to 4, so THU, FRI and SAT are 5, 6, 7. Values may be repeated or given out of order - the compiler only fills in what you leave out.

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