Discussion
What is the output of this program?
#include <stdio.h>
int main(){
struct leader
{
char *lead;
int born;
};
struct leader l1 = {"AbdulKalam", 1931};
struct leader l2 = l1;
printf("%s %d", l2.lead, l1.born);
}
Answer: C
Correct answer: AbdulKalam 1931
l2 = l1 copies the structure member by member - the born value and the lead pointer. That is a shallow copy: both structures now point at the same string literal. Here it does no harm, since neither modifies it.
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