Discussion
What aspect ratio does a delta wing swept \( 45 \) degrees at the leading edge have?
Answer: A
Substituting into \( 4/\tan\Lambda \) with \( \tan 45^\circ = 1 \) gives exactly 4. Comparing with the 60-degree case shows how quickly the aspect ratio falls as sweep is increased, which is the geometric price paid for keeping the leading edge subsonic at high Mach number.
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