Discussion
An aircraft at \( M = 2 \) has its wing swept \( 60 \) degrees. The Mach number of the component normal to the leading edge is
Answer: B
The normal component Mach number is \( M \cos\Lambda = 2 \times \cos 60^\circ = 2 \times 0.5 = 1.0 \). The edge is therefore exactly sonic, sitting precisely on the boundary between the subsonic and supersonic leading-edge cases.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development