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A supersonic aircraft cruises at \( M = 1.8 \). The minimum leading-edge sweep for a subsonic edge is nearest to

  • A.33.7 degrees
  • B.60.0 degrees
  • C.70.5 degrees
  • D.56.3 degrees

Answer: D

The Mach angle is \( \arcsin(1/1.8) = 33.7 \) degrees, so the sweep must exceed \( 90 - 33.7 = 56.3 \) degrees. The distractor 33.7 degrees is the Mach angle itself, which is the complement of the answer and the commonest slip in this calculation.

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