Discussion
An intermediate frequency of \( 455 \ \mathrm{kHz} \) is used. A spurious response appears when a signal arrives \( 227.5 \ \mathrm{kHz} \) from the oscillator. This is
Answer: B
A signal half an intermediate frequency from the oscillator produces the half-IF spurious response, because its second harmonic beats with the oscillator's second harmonic to land in the passband:
\[ 2 \times 227.5 = 455 \ \mathrm{kHz} \]
The image lies a full two intermediate frequencies from the signal instead. Recognising a spurious response by its offset is how the mixing order responsible for it is identified.
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