Discussion
A filter is \( 2.4 \ \mathrm{kHz} \) wide and the receiver's noise figure is \( 10 \ \mathrm{dB} \). Its noise floor is about
Answer: B
Building up from the reference density:
\[ \begin{aligned} P &= -174 + 10\log_{10}(2400) + 10 \\ &= -174 + 34 + 10 = -130 \ \mathrm{dBm} \end{aligned} \]
so about -130 dBm. Subtracting rather than adding the noise figure gives -140 dBm, and -174 dBm is the density before any bandwidth is applied. Narrow filtering is what puts a single sideband receiver's floor this low, and it is why bandwidth is chosen to match the mode.
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