Discussion
A receiver's dial reads \( 1000 \ \mathrm{kHz} \) but the station is actually at \( 1010 \ \mathrm{kHz} \). With a \( 6 \ \mathrm{kHz} \) passband the result is
Answer: C
A ten kilohertz error against a six kilohertz passband puts the carrier outside the flat region:
\[ \begin{aligned} \text{error} &= 10 \ \mathrm{kHz} \\ \text{half-passband} &= 3 \ \mathrm{kHz} \end{aligned} \]
so one sideband is attenuated more than the other and the result is reduced output with distortion rather than silence, since the skirts still pass something. Asymmetric sideband attenuation is the mechanism, and it is why accurate tuning matters more as a filter narrows.
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development