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A receiver's dial reads \( 1000 \ \mathrm{kHz} \) but the station is actually at \( 1010 \ \mathrm{kHz} \). With a \( 6 \ \mathrm{kHz} \) passband the result is

  • A.Normal reception, because the automatic gain control compensates for it
  • B.A heterodyne whistle at the ten kilohertz difference frequency
  • C.Reduced output and distortion
  • D.Complete silence, since the signal falls entirely outside the passband

Answer: C

A ten kilohertz error against a six kilohertz passband puts the carrier outside the flat region:

\[ \begin{aligned} \text{error} &= 10 \ \mathrm{kHz} \\ \text{half-passband} &= 3 \ \mathrm{kHz} \end{aligned} \]

so one sideband is attenuated more than the other and the result is reduced output with distortion rather than silence, since the skirts still pass something. Asymmetric sideband attenuation is the mechanism, and it is why accurate tuning matters more as a filter narrows.

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