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An intermediate frequency amplifier gives \( 60 \ \mathrm{dB} \) of gain and the mixer has \( 6 \ \mathrm{dB} \) of conversion loss. The net gain from mixer input to detector is

  • A.66 dB
  • B.10 dB, the ratio of the two decibel figures as quoted
  • C.360 dB, the product of the two decibel figures as quoted
  • D.54 dB

Answer: D

Gains and losses add in decibels once the sign is respected:

\[ -6 + 60 = 54 \ \mathrm{dB} \]

giving 54 dB. Adding without regard to sign gives 66 dB, and the remaining options multiply or divide quantities that should be added. Working in decibels reduces a cascade to arithmetic, but only if a loss is entered as a negative gain, which is the single convention the notation depends on.

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