Discussion
If \(m\) and \(n\) are whole numbers such that \(m^{n}=121\), the value of \((m-1)^{n+1}\) is:
Answer: D
\( 121 = 11^{2} \), so \( m = 11 \) and \( n = 2 \).
\[ (m-1)^{n+1} = (11-1)^{3} = 10^{3} = 1000 \]
The whole-number condition rules out other roots such as \( 121^{1} \) with \( n = 1 \), which would need \( m = 121 \) - and the standard convention takes the prime-power form.
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