Discussion
If \(3^x - 3^{x-1} = 18\), then the value of \(x^x\) is:
Answer: A
\(3^x - 3^{x-1} = 18 \)
\(\Rightarrow 3^{x-1} \times (3-1) = 18 \)
\(\Rightarrow 3^{x-1} = 9 = 3^2 \)
\(\Rightarrow x-1 = 2 \)
\(\Rightarrow x = 3\).
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