Discussion
If \(2^{(x-y)} = 8\) and \(2^{(x+y)} = 32\), then \(x\) is equal to:
Answer: B
\(2^{(x-y)} = 8 = 2^3 \)
\(\Rightarrow x-y = 3 ....(1) \)
\(2^{(x+y)} = 32 = 2^5 \)
\(\Rightarrow x+y = 5 ....(2)\)
On solving (1) & (2), we get \(x = 4.\)
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