Discussion
A cylindrical rotor synchronous motor develops its maximum torque at a torque angle of
Answer: A
Correct answer: 90 degrees
Since \( P = (EV/X_s)\sin\delta \), the power and hence the torque is greatest where \( \sin\delta = 1 \), that is at \( \delta = 90 \) electrical degrees, giving
\[ P_{max} = \frac{EV}{X_s} \]Beyond that angle the developed torque falls while the load torque does not, so the rotor cannot recover and slips poles. Steady operation is therefore confined to angles well below 90 degrees, typically 20 to 30 at full load, to leave a margin against transient disturbances.
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