Discussion
The processor utilisation of a task set is
Answer: C
Correct answer: the sum of each task's execution time divided by its period
\[ U = \sum \frac{C_i}{T_i}. \] Each term is the fraction of the processor that task requires on average, and the sum is what the whole set demands. It is the first figure computed in any schedulability analysis, because a set demanding more than the processor has cannot be scheduled by any means whatever.
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