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A design has a 3 ms task and a 10 ms task. Rounding the second period to 9 ms would

  • A.make the set harmonic and raise the schedulable utilisation
  • B.reduce the utilisation of the set
  • C.reverse the rate monotonic priority order
  • D.have no effect on the analysis whatever

Answer: A

Nine is exactly three threes, so the releases align and the full processor becomes available under fixed priorities. The utilisation rises slightly, since the task now runs more often, and the priority order is unchanged.

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