Discussion
A periodic task released every 20 ms with an execution time of 5 ms leaves the processor idle for
Answer: C
Correct answer: 15 ms in every period, if nothing else runs
\[ 20 - 5 = 15\ \mathrm{ms}. \] The task uses a quarter of the processor and leaves three quarters, which is the slack available for lower priority work - and the same figure expressed the other way is its utilisation of 0.25.
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