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The amount of heat to be withdrawn from 3 kg of water at 0°C to obtain 3 kg of ice at 0°C in an icemaker is (latent heat of fusion of ice is 80 kcal/kg)

  • A.400 kcal
  • B.160 kcal
  • C.320 kcal
  • D.80 kcal
  • E.240 kcal

Answer: E

The heat withdrawn is 240 kcal.

Water and ice are both at \(0^{\circ}\)C, so only the latent heat of fusion is removed:

\[ Q = mL = 3 \times 80 = 240\ \text{kcal} \]

80 kcal is the amount for 1 kg, and 160, 320 and 400 kcal correspond to 2, 4 and 5 kg.

Removing the same heat from water already at 0°C changes its state without lowering its temperature; cooling to below 0°C would need the specific heat of ice as well, which this question does not involve.

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