Discussion
If the temperature of 2 moles of krypton gas is increased from -11°C to 89°C at constant volume, then (specific heat at constant volume of krypton is CV)
Answer: D
The amount of heat added is 200 CV.
At constant volume no work is done (\(W = P\Delta V = 0\)), so by the first law all the heat supplied goes into internal energy. The temperature rises by \(89 - (-11) = 100\) degrees, and with \(C_{V}\) the molar heat capacity at constant volume,
\[ Q = nC_{V}\Delta T = 2 \times C_{V} \times 100 = 200\,C_{V} \]
The internal energy also increases by \(200\,C_{V}\), not 100 \(C_{V}\), which forgets the 2 moles. No work is done on or by the gas, and the internal energy certainly changes, since the temperature rises.
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