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Sample86 is run - what will be the output?

public class Sample86
{
    static int total;

    public static void main(String[] args) throws InterruptedException
    {
        Thread t = new Thread(() -> { for (int i = 1; i <= 4; i++) total += i; });
        t.start();
        t.join();
        System.out.println(total);
    }
}

  • A.Either 0 or 10, depending on visibility
  • B.10
  • C.0
  • D.4

Answer: B

Correct answer: 10

The loop adds 1 through 4, giving 10. The visibility concern the fourth option raises is real for an unsynchronised static field, but join establishes a happens-before relationship: everything the joined thread did is guaranteed visible to the thread that joins it. So main is certain to see 10, and no volatile or synchronisation is needed here.

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