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The equation of line which is parallel to \(\frac{2 - x}{-3} = \frac{y - 2}{2} = \frac{z - 4}{1}\) and passing through the point (1,1,1) , is

  • A.\(\frac{x - 1}{3} = \frac{y - 1}{2} = \frac{z + 1}{1}\)
  • B.\(\frac{x - 1}{3} = \frac{y - 1}{2} = \frac{z - 1}{1}\)
  • C.\(\frac{x - 1}{3} = \frac{y - 1}{-2} = \frac{z - 1}{1}\)
  • D.\(\frac{x - 1}{-3} = \frac{y - 1}{2} = \frac{z - 1}{1}\)
  • E.\(\frac{x - 1}{3} = \frac{y - 1}{2} = \frac{z + 1}{-1}\)

Answer: B

The line is \(\frac{x - 1}{3} = \frac{y - 1}{2} = \frac{z - 1}{1}\).

First put the given line in standard form. \(\frac{2 - x}{-3} = \frac{x - 2}{3}\), so the line is \(\frac{x - 2}{3} = \frac{y - 2}{2} = \frac{z - 4}{1}\), with direction ratios 3, 2, 1.

A parallel line through (1, 1, 1) has the same direction ratios, giving the keyed equation. Taking the -3 at face value gives direction (-3, 2, 1), which ignores the sign of \(2 - x\). The options with \(z + 1\) pass through \(z = -1\), not 1.

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